Have any questions?
[email protected]
English
Vietnamese
French
Spanish
Korean
Japanese
Thai
Chinese
Indonesian
Login
Signup
Contact
Login
Home
If a and b are whole numbers such that ab = 121, then find the value of (a – 1)b + 1
Question 1:
If a and b are whole numbers such that ab = 121,
then find the value of (a – 1)b + 1
A.
0
B.
10
C.
10 ^2
D.
10^3
Feedback
121 = 11^2 , hence value of a = 11 and b = 2 can be considered.
Therefore, the value of (a – 1)^b + 1 = (11 – 1)^2 + 1= 10^3
These questions are from this test. Would you like to take a practice test?
Practice Surds and Indices Online Test 5 | Englishfreetest.com
20 minutes
10 questions
Do test
Some questions from the same exam
The simplified form of (x^7/2 / x^5/2).√y3 /√y )is :
If 5√5 * 5^3 ÷ 5^-3/2 = 5^a+2 , the value of a is:
The value of (12x^2y^4z^3) ÷ (2xy^2 × 3yz^2) will be :
If a and b are whole numbers such that ab = 121,
then find the value of (a – 1)b + 1
If 4 (x – y) = 64 and 4 (x + y) = 1024, then find the value of x.
If 9^x – 9^x – 1 = 648, then
find the value of x^x
Simplify ( 6a^-2bc^-3/4ab^-3c^2 ) ÷ ( 5a^-3 b^2^-1/3ab^-2c^3 )
If m and n are whole numbers such that m^n = 121,
the value of (m - 1)^n + 1 is:
L√M is surd of order ........, where M is a rational number; L is a positive integer and L√M is irrational.
( 42 x 229 ) ÷ ( 9261)^1/3 = ?
Some other questions you may be interested in
Time and tide ……………………………. for none.
Bread and butter ………………………….. served for breakfast.
The horse and carriage ………………………… waiting at the door.
Slow and steady ……………………….. the race.
…………………………… she know what she is doing?
She ……………………………. one project when she started working on the next.