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- If m and n are whole numbers such that m^n = 121, the value of (m - 1)^n + 1 is:
Question 1:
If m and n are whole numbers such that m^n = 121,the value of (m - 1)^n + 1 is:
A. 1000
Feedback We know that 11^2 = 121.
Putting m = 11 and n = 2, we get:
(m - 1)^n + 1 = (11 - 1)^(2 + 1) = 10^3 = 1000.
Putting m = 11 and n = 2, we get:
(m - 1)^n + 1 = (11 - 1)^(2 + 1) = 10^3 = 1000.
B. 100
C. 10
D. 1
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