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- I. (x^9/4 ÷ 9)2 = 27 ÷ x^5/2 II. y^1/4 × y^3/4 × 2401 = 49 × y^3
Question 1:
I. (x^9/4 ÷ 9)2 = 27 ÷ x^5/2 II. y^1/4 × y^3/4 × 2401 = 49 × y^3
A. if x > y
B. if x < y
C. if x ≥ y
D. if x = y or relationship between x and y can't be established
Feedback According to the given equations:
I. (x^9/4 ÷ 9)^2 = 27 ÷ x^5/2
x9/2/81 = 27/x^5/2
x^9/2 × x^5/2 = 81 × 27
x7 = 3^4 × 3^3
x = 3
II. y^1/4 × y^3/4 × 2401 = 49 × y
y × 2401 = 49 × y^3
2401/49 = y^2
y = ± 7
After comparison of both equations, the conclusion
Option D is correct.
I. (x^9/4 ÷ 9)^2 = 27 ÷ x^5/2
x9/2/81 = 27/x^5/2
x^9/2 × x^5/2 = 81 × 27
x7 = 3^4 × 3^3
x = 3
II. y^1/4 × y^3/4 × 2401 = 49 × y
y × 2401 = 49 × y^3
2401/49 = y^2
y = ± 7
After comparison of both equations, the conclusion
Option D is correct.
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