• Home
  • I. 2x^4 – 36x^2 + 162 = 0II. 3y^4 – 75y^2 + 432 = 0
Question 1:
I. 2x^4 – 36x^2 + 162 = 0
II. 3y^4 – 75y^2 + 432 = 0
A. if x > y
B. if x ≤ y
C. if x ≥ y
D. if x = y or relationship between x and y can't be established
Feedback I. 2x^4 – 36x^2 + 162 = 0
x^4 – 18x^2 + 81 = 0
x^4 – 9x^2 – 9x^2 + 81 = 0
x^2 (x^2 – 9) – 9(x^2 – 9) = 0
(x^2 – 9) (x^2 – 9) = 0
x^2 = 9 ; x = ± 3
II. 3y^4 – 75y^2 + 432 = 0
y4 – 25y2 + 144 = 0
y^4 – 16y^2 – 9y^2 + 144 = 0
y^2 (y^2 – 16) – 9 (y^2 – 16) = 0
(y^2 – 9) (y^2 – 16) = 0
y^2 = 9; y^2 = 16
y = ± 3, y = ± 4
After comparison of both equations, the conclusion is, x = y or no relation is obtained
Hence, option D is correct.

These questions are from this test. Would you like to take a practice test?

Practice Quadratic Equation Questions Online Test 5 | Englishfreetest.com

  • 20 minutes
  • 10 questions
Do test

Some questions from the same exam

Some other questions you may be interested in