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Find the sum of all the 4 digit numbers that can be formed with the digits 3, 4, 5 and 6

A.119988
B.11988
C.191988
D.None of these
Answer and Feedback
Answer:A
Feedback:No. of Digits = 4 All are distinct; They can be arranged in 4! = 24 ways
Each of the digits 3, 4, 5 and 6 occur at unit place = 3! Ways = 6 ways.
Thus there will be 6 numbers ending with 3, 4, 5 and 6 each. So the sum of the digits at unit's place = 6(3 + 4 + 5 + 6) =108
The sum of numbers = 108 × 103 + 108 × 102 + 108 × 101 + 108 × 100 = 119988

Questions in to this exercise. Do you want test?

Practice Permutations Online Test 2 | Englishfreetest.com

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