B. 4550
Feedback Here we need the number of possible combinations of 3 out of 5 freshmen,5C3, and the number of possible combinations of 3 out of the 15 sophomores and juniors,15C3. Note that we want 3 freshmen and 3 students from the other classes. Therefore, we multiply the number of possible groups of 3 of the 5 freshmen times the number of possible groups of 3 of the 15 students from the other classes. 5C3×15C3=4,550.