Three triangles, △LMN, △PQR and △CDE are formed in such a way that the inside triangle is formed by joining the midpoints of the sides of outside triangle.
Question 1:
Three triangles, △LMN, △PQR and △CDE are formed in such a way that the inside triangle is formed by joining the midpoints of the sides of outside triangle. △LMN is the outermost triangle while △CDE is the innermost triangle. The length of the sides of inner most triangle are CD = 3, DE = 8 and CE = 4. Find the perimeter of the outermost triangle.
A.30
B.60
Feedback∴ Perimeter of △PQR = 2 x Perimeter of △CDE = 2(3+8+4) = 30 Perimeter of △LMN = 2 x Perimeter of △PQR = 2 x 30 = 60
C.72
D.90
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