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Question 1:
The difference between two parallel sides of a trapezium is 4 cm. perpendicular distance between them is 19 cm. If the area of the trapezium is 475
A. 27 and 23
Feedback Let the two parallel sides of the trapezium be a cm and b cm.
Then, a - b = 4
And, 1/2×(a+b)×19=475=>(a+b)=50
Solving (i) and (ii), we get: a = 27, b = 23.
So, the two parallel sides are 27 cm and 23 cm
B. 24 and 23
C. 25 and 23
D. 22 and 23

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