D. b ≠ l
Feedback The given equation x3 – ax2 + bx – a = 0 can be rewritten as:
x (x2 + b) – a(x2 + 1) = 0
In case b = 1, then the equation becomes (x – a)( x2 + 1) = 0
Now here x2 + 1 = 0 will give imaginary roots.
Hence, if the given equation has three real roots, then b ≠ 1.