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- Xavier can do a job in 40 days.
Question 1:
Xavier can do a job in 40 days. He worked on it for 5 days and then Paes finished it in 21 days.In how many days Xavier and Paes can finish the work?
A. 10 Days
B. 20 Days
C. 15 Days
Feedback Xavier’s one day’s work = 1/40
His 5 days work = 1/40 × 5 = 1/8
The work remaining = 1 – 1/8 = 7/8
7/8 of the work is done by Paes in 21 days
Then, his 1 day’s work = 7/8/21 = 7/21 × 8 = 1/24
Therefore, the time taken by Paes to finish the whole work = 24 days.
Then. The No. of days two of them together take to finish the work = 40 × 24/40 + 24
= 40 × 24/64 = 15 days.
His 5 days work = 1/40 × 5 = 1/8
The work remaining = 1 – 1/8 = 7/8
7/8 of the work is done by Paes in 21 days
Then, his 1 day’s work = 7/8/21 = 7/21 × 8 = 1/24
Therefore, the time taken by Paes to finish the whole work = 24 days.
Then. The No. of days two of them together take to finish the work = 40 × 24/40 + 24
= 40 × 24/64 = 15 days.
D. 25 Days
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