B. 1/27
Feedback We have total possible outcomes on rolling a dice = 6
Total favourable outcomes = 2
Probability of getting 3 or 4 in first throw of dice = 2/6 = 1/3
Probability of getting 3 or 4 in first throw of dice = 2/6 = 1/3
Probability of getting 3 or 4 in first throw of dice = 2/6 = 1/3
Hence P(getting 3 or 4 in 3 consecutive rolls of a dice) = 1/3 × 1/3 × 1/3 = 1/27