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Question 1:
What is the probability of getting 3 or 4 in 3 consecutive rolls of a dice?
A. 1/6
B. 1/27
Feedback We have total possible outcomes on rolling a dice = 6
Total favourable outcomes = 2
Probability of getting 3 or 4 in first throw of dice = 2/6 = 1/3
Probability of getting 3 or 4 in first throw of dice = 2/6 = 1/3
Probability of getting 3 or 4 in first throw of dice = 2/6 = 1/3
Hence P(getting 3 or 4 in 3 consecutive rolls of a dice) = 1/3 × 1/3 × 1/3 = 1/27
C. 1/16
D. ¼

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