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What is the area of the trapezoid with parallel sides having the lengths 26 and 32, the perpendicular distance between them is 15?

A.870 sq. units
B.435 sq. units
C.370 sq. units
D.280 sq. units
Answer and Feedback
Feedback:Area of trapezoid =1/2(a+b)×h
Where, a + b = sum of the parallel sides and h = perpendicular distance between them.
∴ a + b = 26 + 32 = 58 and h = 15
Area of trapezoid =1/2(58)(15)=435 sq. units

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