Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. The marks obtained by them are
A.42,30
B.42,31
C.42,32
D.42,33
FeedbackLet their marks be (x+9) and x. Then, x+9 = 56/100(x + 9 +x) => 25(x+9) => 14 (2x + 9) => 3x = 99 => x = 33. So, their marks are 42 and 33
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