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Question 1:
Two pipes A and B Can fill a tank in 12 hours and 1 day respectively. A pipe C can empty the tank in 10 hours. If Pipe C is opened after 3 hours from the pipe A & B are opened,
then find the time taken to full the tank.
A. 24 hours
B. 28 hours
Feedback The part of the tank filled in 1 hour = 1/12 + 1/24
Then, the part filled in 3 hours = 3[1/12 + 1/24] = 3/8
Remaining part to be filled = 1 - 3/8 = 5/8
Net part filled in 1 hour when A, B & C are opened = 1/12 + 1/24 - 1/10 = 1/40
Now, 1/40 part is filled in 1 hour then 5/8 part will be filled in [40 x 5/8] = 25 hours
Therefore, 3/8 part will be filled in 3 hours and 5/8 part filled in 25 hours.
Hence the total time taken to full the tank is 28 hours.
C. 45 hours
D. None of these

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