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- Three unbiased coins are tossed. What is the probability of getting at most two heads?
Question 1:
Three unbiased coins are tossed. What is the probability of getting at most two heads? A. 3/4
B. 1/4
C. 3/8
D. 7/8
Feedback Here S = {TTT, TTH, THT, HTT, THH, HTH, HHT, HHH}
Let E = event of getting at most two heads.
Then E = {TTT, TTH, THT, HTT, THH, HTH, HHT}.
P(E) = n(E)/n(S)=7/8.
Let E = event of getting at most two heads.
Then E = {TTT, TTH, THT, HTT, THH, HTH, HHT}.
P(E) = n(E)/n(S)=7/8.
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