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The volumes of two cones are in the ratio 1 : 10 and the radii of the cones are in the ratio of 1 : 2.
Question 1:
The volumes of two cones are in the ratio 1 : 10 and the radii of the cones are in the ratio of 1 : 2. What is the length of the wire?
A.
2 : 5
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The volume of the cone = (1/3)πr^2h
Only radius (r) and height (h) are varying.
Hence, (1/3)π may be ignored.
V1/V2 = r1^2h1/r2^2h2 => 1/10 = (1)^2h1/(2)^2h2
h1/h2 = 2/5
h1 : h2 = 2 : 5
B.
1 : 5
C.
3 : 5
D.
4 : 5
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