The sum of the squares of two consecutive positive integers exceeds their product by 91.
Question 1:
The sum of the squares of two consecutive positive integers exceeds their product by 91. Find the integers?
A.9, 10
FeedbackLet the two consecutive positive integers be x and x + 1 x² + (x + 1)² - x(x + 1) = 91 x² + x - 90 = 0 (x + 10)(x - 9) = 0 => x = -10 or 9. As x is positive x = 9 Hence the two consecutive positive integers are 9 and 10.
B.10, 11
C.11, 12
D.12, 13
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