The ratio of the area of two square, one having and double its diagonal than the other is?
Question 1:
The ratio of the area of two square, one having and double its diagonal than the other is?
A.2:1
B.3:1
C.3:2
D.4:1
FeedbackLet the diagonal of one square be (2d) cm Then, diagonal of another square = d cm Area of first square = [ 1/2 x (2d)^2] cm^2 Area of second square = (1/2 x d^2) cm^2 Ratio of area = (2d)^2/ d^2= 4/1 = 4: 1
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