- Have any questions?
- [email protected]
- Home
- The present ages of three persons are in proportions 4:7:9.
Question 1:
The present ages of three persons are in proportions 4:7:9. Eight years ago, the sum of their ages was 56. Find their present ages. A. 8, 20, 28
B. 16, 28, 36
Feedback Let their present ages be 4x, 7x and 9x years respectively.
Then, (4x - 8) + (7x - 8) + (9x - 8) = 56
20x = 80 => x = 4
Their present ages are 16, 28 and 36 years respectively.
Then, (4x - 8) + (7x - 8) + (9x - 8) = 56
20x = 80 => x = 4
Their present ages are 16, 28 and 36 years respectively.
C. 20, 35, 45
D. None of these
These questions are from this test. Would you like to take a practice test?