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The difference between two parallel sides of a trapezium is 4 cm. perpendicular distance between them is 19 cm. If the area of the trapezium is 475

A.27 and 23
B.24 and 23
C.25 and 23
D.22 and 23
Answer and Feedback
Feedback:Let the two parallel sides of the trapezium be a cm and b cm.
Then, a - b = 4
And, 1/2×(a+b)×19=475=>(a+b)=50
Solving (i) and (ii), we get: a = 27, b = 23.
So, the two parallel sides are 27 cm and 23 cm

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