Ten years ago A was half of B in age. If the ratio of their present ages is 3: 4, what will be the total of their present ages?
A.30
B.35
FeedbackLet A's age 10 years ago = x years. Then, B's age 10 years ago = 2x years. (x + 10) / (2x+ lO) = 3/4 => x = 5. So, the total of their present ages =(x + 10 + 2x + 10) = (3x + 20) = 35 years.
C.37
D.41
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