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- Six friends decide to share a big cake.
Question 1:
Six friends decide to share a big cake. Since all of them like the cake, they begin quarrelling who gets to first cut and have a piece of the cake. One friend suggests that they have a blindfold friend choose from well shuffled set of cards numbered one to six. You check and find that this method works as it should simulate a fair throw of a die. You check by performing multiple simultaneous trials of picking the cards blindfold and throwing a die. You note that the number shown by the method of picking up a card and throwing a real world die, sums to a number between 2 and 12.Which total would be likely to appear more often – 8, 9 or 10?
A. 8
Feedback Given that there are two cases
One is choosing a card from well shuffled cards and other one is throwing a die
In first case there are 6 possible ways (1, 2, 3, 4, 5, 6)
In second case also there are 6 possible ways (1, 2, 3, 4, 5, 6)
When we use both cases simultaneously there are 36 possible cases
Possibility of getting sum 8 = (2,6), (6,2), (3,5), (5,3), (4,4) = 5
Possibility of getting sum 9 = (3,6), (6,3), (4,5), (5,4) = 4
Possibility of getting sum 10 = (4,6), (6,4), (5,5) = 3
When we use two methods simultaneously more often occurring sum = 8
One is choosing a card from well shuffled cards and other one is throwing a die
In first case there are 6 possible ways (1, 2, 3, 4, 5, 6)
In second case also there are 6 possible ways (1, 2, 3, 4, 5, 6)
When we use both cases simultaneously there are 36 possible cases
Possibility of getting sum 8 = (2,6), (6,2), (3,5), (5,3), (4,4) = 5
Possibility of getting sum 9 = (3,6), (6,3), (4,5), (5,4) = 4
Possibility of getting sum 10 = (4,6), (6,4), (5,5) = 3
When we use two methods simultaneously more often occurring sum = 8
B. All are equally likely
C. 9
D. 10
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