- Have any questions?
- [email protected]
- Home
- Meena’s present age is three times her son’s present age and two fifth of her father’s present age.
Question 1:
Meena’s present age is three times her son’s present age and two fifth of her father’s present age. The average present age of all of them is 46 years.What is the difference between the Meena’s son’s present age and Meena’s father’s present age?
A. 56 years
B. years
C. 78 years
Feedback The ratio of present age of Meena and her son’s age = 3 : 1 (3x, x)
Meena’s present age = (2/5)*Meena’s father’s present age
Meena’s father’s present age = (15/2)x
According to the question,
x + 3x + (15/2) x = 138
(2x + 6x + 15x)/2 = 138
23x = 138*2
x = 12
Required difference = 90 – 12 = 78 years
Meena’s present age = (2/5)*Meena’s father’s present age
Meena’s father’s present age = (15/2)x
According to the question,
x + 3x + (15/2) x = 138
(2x + 6x + 15x)/2 = 138
23x = 138*2
x = 12
Required difference = 90 – 12 = 78 years
D. 72 years
These questions are from this test. Would you like to take a practice test?