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- In the quadratic equation ax^2 - 11x + 40 = 0, if the sum of two roots is 1.
Question 1:
In the quadratic equation ax^2 - 11x + 40 = 0, if the sum of two roots is 1.1, what is the product of the two roots? A. 9
B. 8
C. 5
D. 4
Feedback he sum of the roots of the quadratic equation ax^2 - bx + c = 0 are (-b/a) and the product of the roots are (c/a).
Thus, in the equation ax2 - 11x + 40 = 0, where a = a, b = - 11 and c = 40.
we get, sum of the roots = - (- 11) / a = 1.1
a = 11 / 1.1 = 10
Product of the roots = 40/10 = 4
Thus, in the equation ax2 - 11x + 40 = 0, where a = a, b = - 11 and c = 40.
we get, sum of the roots = - (- 11) / a = 1.1
a = 11 / 1.1 = 10
Product of the roots = 40/10 = 4
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