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- In a two-digit number, the digit in the unit's place is more than twice the digit in ten's place by 1.
Question 1:
In a two-digit number, the digit in the unit's place is more than twice the digit in ten's place by 1. If the digits in the unit's place and the ten's place are interchanged,difference between the newly formed number and the oiginal number is less than the original number by 1. What is the original number ? A. 35
B. 36
C. 37
Feedback Let the ten's digit be x. Then, unit's digit = 2x + 1.
[10x + (2x + 1)] - [{10 (2x + 1) + x} - {10x + (2x + 1)}] = 1
(12x + 1) - (9x + 9) = 1 <=> 3x = 9, x = 3.
So, ten's digit = 3 and unit's digit = 7. Hence, original number = 37.
[10x + (2x + 1)] - [{10 (2x + 1) + x} - {10x + (2x + 1)}] = 1
(12x + 1) - (9x + 9) = 1 <=> 3x = 9, x = 3.
So, ten's digit = 3 and unit's digit = 7. Hence, original number = 37.
D. 39
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