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Question 1:
In a simultaneous throw of pair of dice. Find the probability of getting the total more than 7.
A. 5/12
Feedback Here total number of possible outcomes, n(S) = (6 × 6) = 36
Let (n) is event of getting a total more than 7
Possible pairs of numbers with sum > 7 = {(2, 6), (3, 5), (3, 6), (4, 4), (4, 5),(4, 6), (5, 3), (5, 4), (5, 5), (5, 6), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)}
Therefore, total number of favorable outcomes = 15
P(E) = n (E)/n(S)
P(E) = 15/36
P(E) = 5/12.
B. 7/12
C. 1/3
D. 1/4

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