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Question 1:
In a bag, there are a certain number of toy-blocks with alphabets A, B, C and D written on them. The ratio of blocks A:B:C:D is in the ratio 4:7:3:1. If the number of ‘A’ blocks is 50 more than the number of ‘C’ blocks, what is the number of ‘B’ blocks?
A. 650
B. 480
C. 578
D. 350
Feedback Let the number of the blocks A,B,C,D be 4x, 7x, 3x and 1x respectively
=> 4x = 3x + 50
=> x = 50.
So the number of ‘B’ blocks is 7*50 = 350.

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