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if x:y = 1:3, then find the value of (7x+3y):(2x+y)

A.14:5
B.15:5
C.16:5
D.17:5
Answer and Feedback
Answer:C
Feedback:let x = 1k and y = 3k, so
7(k)+3(3k)/2(k)+1(3k) = 16k/5k = 16:5

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