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- if x:y = 1:3, then find the value of (7x+3y):(2x+y)
Question 1:
if x:y = 1:3, then find the value of (7x+3y):(2x+y) A. 14:5
B. 15:5
C. 16:5
Feedback let x = 1k and y = 3k, so
7(k)+3(3k)/2(k)+1(3k) = 16k/5k = 16:5
7(k)+3(3k)/2(k)+1(3k) = 16k/5k = 16:5
D. 17:5
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