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- If the radius of a circle decreased by 50% its area is decreased by:
Question 1:
If the radius of a circle decreased by 50% its area is decreased by: A. 75%
Feedback Original area = πr^2
New area = π(r/2)^2 = (πr^2)/4
Reduction in area = [(πr^2 - (πr^2)/4]^2 = (3πr^2)/4
Reduction percent = ((3πr^2)/4 × 1/(πr^2 × 100) % = 75%
New area = π(r/2)^2 = (πr^2)/4
Reduction in area = [(πr^2 - (πr^2)/4]^2 = (3πr^2)/4
Reduction percent = ((3πr^2)/4 × 1/(πr^2 × 100) % = 75%
B. 50%
C. 85%
D. 65%
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