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- If m and n are whole numbers such that m^n = 121, the value of (m − 1)^n + 1 is:
Question 1:
If m and n are whole numbers such that m^n = 121,the value of (m − 1)^n + 1 is:
A. 1
B. 10
C. 121
D. 1000
Feedback We know that 11^2 = 121.
Putting m = 11 and n = 2, we get:
(m − 1)^n + 1 = (11 − 1)^(2 + 1) = 103 = 1000.
Putting m = 11 and n = 2, we get:
(m − 1)^n + 1 = (11 − 1)^(2 + 1) = 103 = 1000.
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