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If a and b are whole numbers such that a^b = 121, then find the value of (a – 1)^b + 1
Question 1:
If a and b are whole numbers such that a^b = 121, then find the value of (a – 1)^b + 1
A.
0
B.
10
C.
10^2
D.
10^3
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121 = 11^2 , hence value of a = 11 and b = 2 can be considered.
Therefore, the value of (a – 1)^b + 1 = (11 – 1)^2 + 1= 10^3
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