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- If 1/a+1/b+1/c = 1/(a+b+c) where a+b+c not equals '0', abc not equals '0', What is the value of (a+b) (b+c) (a+c) ?
Question 1:
If 1/a+1/b+1/c = 1/(a+b+c) where a+b+c not equals '0', abc not equals '0',What is the value of (a+b) (b+c) (a+c) ?
A. 3
B. 2
C. 0
Feedback Let assume the value of a,b &c that will satisfy the equation.
so a=1,b=1,c= -1 or a=1,b= -1 &c=1 or a= -1,b=1,c=1
here all three cases satisfy the equation
assume any one a=1,b=1,c= -1
Hence (a+b)(b+c)(c+a)=(1+1)(1-1)(-1+1) = 0
so a=1,b=1,c= -1 or a=1,b= -1 &c=1 or a= -1,b=1,c=1
here all three cases satisfy the equation
assume any one a=1,b=1,c= -1
Hence (a+b)(b+c)(c+a)=(1+1)(1-1)(-1+1) = 0
D. 1
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