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  • I. x^2 – (729)1/6 x – 4 = 0II. y^2 – 8y + 16 = 0
Question 1:
I. x^2 – (729)1/6 x – 4 = 0
II. y^2 – 8y + 16 = 0
A. if x < y
B. if x ≤ y
Feedback Correct Option: B
According to the given equations :
I. x^2 – (729)1/6 x – 4 = 0
x^2 – 3x – 4 = 0
x^2 – 4x + x – 4 = 0
x(x – 4) + 1 (x – 4) = 0
x = – 1, 4
II. y^2 – 8y + 16 = 0
y^2 – 4y – 4y + 16 = 0
y (y – 4) – 4 (y – 4) = 0
y = 4, 4
After comparison of both equations, the conclusion is, x ≤ y
C. if x ≥ y
D. if x < y

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