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- I. a^2 - 7a + 12 = 0, b^2 - 3b + 2 = 0 to solve both the equations to find the values of a and b?
Question 1:
I. a^2 - 7a + 12 = 0,b^2 - 3b + 2 = 0 to solve both the equations to find the values of a and b?
A. if a < b
B. if a ≤ b
C. if the relationship between a and b cannot be established.
D. if a > b
Feedback I.(a - 3)(a - 4) = 0
a = 3, 4
II. (b - 2)(b - 1) = 0
b = 1, 2
a > b
a = 3, 4
II. (b - 2)(b - 1) = 0
b = 1, 2
a > b
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