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Question 1:
I. a^2 - 13a + 42 = 0,b^2 - 15b + 56 = 0 to solve both the equations to find the values of a and b?
A. If a > b
B. If a ≥ b
C. If a < b
D. If a ≤ b
Feedback I. a^2 - 13a + 42 = 0
(a - 6)(a - 7) = 0 => a = 6, 7
II. b^2 - 15b + 56 = 0
(b - 7)(b - 8) = 0 => b = 7, 8
>a ≤ b
(a - 6)(a - 7) = 0 => a = 6, 7
II. b^2 - 15b + 56 = 0
(b - 7)(b - 8) = 0 => b = 7, 8
>a ≤ b
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