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I.
Question 1:
I. 9a^2 + 18a + 5 = 0,
2b^2 + 13b + 20 = 0 to solve both the equations to find the values of a and b?
A.
If a > b
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1.9a2 + 3a + 15a + 5 = 0 =>(3a + 5)(3a + 1) = 0 => a = -5/3, -1/3
II. 2b2 + 8b + 5b + 20 = 0
=>(2b + 5)(b + 4) = 0 => b = -5/2,-4
a is always more than b.
a > b.
B.
If a ≥ b
C.
If a < b
D.
If a ≤ b
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