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- Father is four times more than the age of his daughter.
Question 1:
Father is four times more than the age of his daughter. If after 5 years, he would be four times of daughter’s age, then further after 5 years, how many times he would be of his daughter’s age? A. 1.5 time
B. 2 times
C. 3.4 times
Feedback Let the daughter's age be y and father's age be 4y.
Father’s age is 4 times more aged than his daughter, therefore father’s present age = y + 4y = 5y
After five years, father’s age will be three times his daughter age.
(5y + 5) = 4(y + 5)
y = 15
After 5 years it was (4y + 5), then after further 5 years, father’s age = (5y+10) and daughter’s age = (y + 10)
(5y + 10) / (y + 10) = ?
Substituting the value of y, we get
[(5x15) + 10] / [15+10] = 85/25 = 17/5= 3.4 times
After another 5 years, father will be 3.4 times of daughter's age.
Father’s age is 4 times more aged than his daughter, therefore father’s present age = y + 4y = 5y
After five years, father’s age will be three times his daughter age.
(5y + 5) = 4(y + 5)
y = 15
After 5 years it was (4y + 5), then after further 5 years, father’s age = (5y+10) and daughter’s age = (y + 10)
(5y + 10) / (y + 10) = ?
Substituting the value of y, we get
[(5x15) + 10] / [15+10] = 85/25 = 17/5= 3.4 times
After another 5 years, father will be 3.4 times of daughter's age.
D. 3 times
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