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- A single pipe of diameter x has to be replaced by six pipes of diameters 12 cm each.
Question 1:
A single pipe of diameter x has to be replaced by six pipes of diameters 12 cm each. The pipes are used to covey some liquid in a laboratory.If the speed/flow of the liquid is maintained the same then the value of x is ?
A. 14.69 cm
B. 29.39 cm
Feedback Volume of water flowing through 1 pipe of diameter x = Volume discharged by 6 pipes of diameter 12 cms.
As speed is same, area of cross sections should be same.
Area of bigger pipe of diameter x = Total area of 6 smaller pipes of diameter 12
i.e πR^2 = 6πR1^2
Here R = R and R1 = 12/2 = 6
⇒R^2 = 6×6×6
R = 14.696
=> D = X = 14.696 * 2 = 29.3938 cm.
As speed is same, area of cross sections should be same.
Area of bigger pipe of diameter x = Total area of 6 smaller pipes of diameter 12
i.e πR^2 = 6πR1^2
Here R = R and R1 = 12/2 = 6
⇒R^2 = 6×6×6
R = 14.696
=> D = X = 14.696 * 2 = 29.3938 cm.
C. 18.65 cm
D. 22.21 cm
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