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A rectangular block has the dimensions 5x6x7 cm it is dropped into a cylindrical vessel of radius 6cm and height 10 cm. If the level of the fluid in the cylinder rises by 4 cm,
What portion of the block is immersed in the fluid ?

A.22/7 x 24/35
B.22/7 x 36/4
C.22/7 x 36/5
D.22/7 x 37/21
Answer and Feedback
Answer:A
Feedback:Since level of water increased in cylinder by height 4.
This is because of the rectangular block .
Therefore , area of rectangular block immersed in water is
= 22/7×6×6×4
Thats why portion of block immersed in water is
= (22/7 * 36 * 4) / total vol. of rectangle
= (22/7 * 36 * 4)/ (7*5*6)

= (22/7 * 24)/ 35.

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