A chemist has 10L of a solution that is 10% nitric acid by volume.
Question 1:
A chemist has 10L of a solution that is 10% nitric acid by volume. He wants to dilute the solution to 4% strength by adding water. How many litres of water must be add?
A.40 L
B.33 L
C.25 L
D.15 L
FeedbackQuantity of nitric acid = 10 *(1/10) = 1 L Water = 10 – 1 = 9 L Let x litre of water be added, (10 + x ) * (4/100) = 1 => x = 15 L
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