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Question 1:
A can contains a mixture of two liquids A and B in the ratio 7: 5. When 9 liters of the mixture is drawn off and the can is filled with B, the ratio of A and B becomes 7: 9. How many liters of liquid A was contained by the can initially?
A. 10
B. 20
C. 21
Feedback Suppose the can initially contain 7x and 5x liters of mixtures A and B respectively
Quantity of A in mixture left =(7x - 7/12 x 9) = (7x - 21/4) litres.
Quantity of B in mixture left = (5x - 5/12 x 9) = (5x - 15/4) litres.
(7x - 21/4)/[(5x - 15/4 + 9)] = 7/9
=> 252x -189 = 140x + 147
=> x =3.
So, the can contain 21 liters of A.
D. 25

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