C. 2/3
Feedback Let original weight of bucket when it is filled with water = x
Then weight of bucket = (25/100) * x = x/4
Original weight of water = x – (x/4) = 3x/4
Now when some water removed, new weight of bucket with remaining water = (50/100) * x = x/2
So new weight of water = new weight of bucket with remaining water – weight of bucket = [(x/2) – (x/4)] = x/4
So part of water removed = [(3x/4) – (x/4)]/(3x/4)