- Have any questions?
- [email protected]
- Home
- 8 % of the voters in an election did not cast their votes in the election, there were only two candidates.
Question 1:
8 % of the voters in an election did not cast their votes in the election, there were only two candidates. The winner by obtaining 48 % of the total votes defeated his contestant by 1100 votes.The total number of voters in the election was.
A. 27500
Feedback Let the total number of voters be x
Votes cast = 92 % of x = (92/100 × x) = 23x/25
Votes in favour of winning candidate = 48/100 × x
= 12x/25
Votes polled by defeated candidate = (23x/25 – 12x/25)
= 11x/25 12x/25 – 11x/25 = 1100
=> 12x – 11x = 27500
=> x = 27500
Votes cast = 92 % of x = (92/100 × x) = 23x/25
Votes in favour of winning candidate = 48/100 × x
= 12x/25
Votes polled by defeated candidate = (23x/25 – 12x/25)
= 11x/25 12x/25 – 11x/25 = 1100
=> 12x – 11x = 27500
=> x = 27500
B. 21000
C. 22000
D. 26500
These questions are from this test. Would you like to take a practice test?